How much heat is needed to increase the temperature of 20 lb of water from 32°F to 212°F?

To determine the amount of heat needed to increase the temperature of a certain mass of water, you can use the formula:

[ Q = m \times C \times \Delta T ]

where:

• ( Q ) is the heat energy in BTUs,

• ( m ) is the mass of the water in pounds,

• ( C ) is the specific heat capacity of water (approximately 1 BTU/lb°F),

• ( \Delta T ) is the change in temperature in degrees Fahrenheit.

In this case, the mass of water is 20 lb, the initial temperature is 32°F, and the final temperature is 212°F. First, we need to calculate the change in temperature (( \Delta T )):

[ \Delta T = 212°F - 32°F = 180°F ]

Now, substitute the values into the formula:

[ Q = 20 , \text{lb} \times 1 , \text{BTU/lb°F} \times 180°F ]

Calculating that gives:

[ Q = 20 \times 180 = 3600 , \text{BTU} ]

Thus, the amount of heat required to